File: root - text - article - 2019 - 10 - floor-and-ceiling-of-a-binary-search-tree.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Problem, Data Structures and Algorithms, | English | Home Page | Category: Computing | 373 Views, 24687 Search Bots | 119 Words
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Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Problem, Data Structures and Algorithms, | English | Home Page | Category: Computing | 373 Views, 24687 Search Bots | 119 Words
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Hi, here's your problem today. This problem was recently asked by Apple:
Given an integer k and a binary search tree, find the floor (less than or equal to) of k, and the ceiling (larger than or equal to) of k. If either does not exist, then print them as None.
Here is the definition of a node for the tree.
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Problem, Data Structures and Algorithms, | English | Home Page | Cateogry: Computing | 373 Views, 24687 Search Bots | 119 Words Given an integer k and a binary search tree, find the floor (less than or equal to) of k, and the ceiling (larger than or equal to) of k. If either does not exist, then print them as None.
Here is the definition of a node for the tree.
class Node:
def __init__(self, value):
self.left = None
self.right = None
self.value = value
def findCeilingFloor(root_node, k, floor=None, ceil=None):
# Fill this in.
root = Node(8)
root.left = Node(4)
root.right = Node(12)
root.left.left = Node(2)
root.left.right = Node(6)
root.right.left = Node(10)
root.right.right = Node(14)
print findCeilingFloor(root, 5)
# (4, 6)
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