File: root - text - article - 2019 - 11 - falling-dominoes.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, | English | Home Page | Category: Computing | 492 Views, 15775 Search Bots | 117 Words
| Browse | Archive
![Subscribe to Feed Burner Subscribe to Feed Burner](/images/form/rss.gif)
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, | English | Home Page | Category: Computing | 492 Views, 15775 Search Bots | 117 Words
![Subscribe to Feed Burner Subscribe to Feed Burner](/images/form/rss.gif)
Hi, here's your problem today. This problem was recently asked by Twitter:
Given a string with the initial condition of dominoes, where:
. represents that the domino is standing still
L represents that the domino is falling to the left side
R represents that the domino is falling to the right side
Figure out the final position of the dominoes. If there are dominoes that get pushed on both ends, the force cancels out and that domino remains upright.
Example:
Input: ..R...L..R.
Output: ..RR.LL..RR
Here is your starting point:
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, | English | Home Page | Cateogry: Computing | 492 Views, 15775 Search Bots | 117 Words Given a string with the initial condition of dominoes, where:
. represents that the domino is standing still
L represents that the domino is falling to the left side
R represents that the domino is falling to the right side
Figure out the final position of the dominoes. If there are dominoes that get pushed on both ends, the force cancels out and that domino remains upright.
Example:
Input: ..R...L..R.
Output: ..RR.LL..RR
Here is your starting point:
class Solution(object):
def pushDominoes(self, dominoes):
# Fill this in.
print Solution().pushDominoes('..R...L..R.')
# ..RR.LL..RR
![Subscribe to Feed Burner Subscribe to Feed Burner](/images/form/rss.gif)
Related Articles
- Daily Interview Problem: Decode String
- Algorithm Interview: No Adjacent Repeating Characters
- Invert a Binary Tree
- [Daily Problem] Angles of a Clock
- Algorithm Interview: Convert Roman Numerals to Decimal
- Daily Interview Problem: Distribute Bonuses
- Patterns for breaking down questions you haven
- Skip the readings, focus on problems. And use all the hints!
- Plus One
- Algorithm Interview: Permutations of numbers
©2006~2024 SteakOverCooked - 0.01236 Seconds(s) - 1516.419 KB/s - 30 Online
Memory: 493.84 KB
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - Server PHP Version: 7.4.33
How to Cook a Perfect Steak? | <meta name="robots" content="noindex, follow" />
![](/images/top.jpg)
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - Server PHP Version: 7.4.33
Read & Write - Normal - Mini - Post - All Comments - Statistics
Be the first one to comment this page !