To the Top
File:  root - text - article - 2019 - 11 - witness.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 1950 Views, 20539 Search Bots | 94 Words

Subscribe to Feed Burner | Browse | Archive
Hi, here's your problem today. This problem was recently asked by Google:

There are n people lined up, and each have a height represented as an integer. A murder has happened right in front of them, and only people who are taller than everyone in front of them are able to see what has happened. How many witnesses are there?

Example:
Input: [3, 6, 3, 4, 1]
Output: 3
Explanation: Only [6, 4, 1] were able to see in front of them.



 #

 #

 # #

####

####

#####

36341                                 x (murder scene)


Here's your starting point:



def witnesses(heights):

  # Fill this in.



print witnesses([3, 6, 3, 4, 1])

# 3
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Cateogry: Computing | 1950 Views, 20539 Search Bots | 94 Words Subscribe to Feed Burner

Related Articles

  1. Algorithm Interview Question: Max and Min with Limited Comparisons
  2. Algorithm Interview: Longest Consecutive Sequence
  3. Absolute Path
  4. Daily Interview Problem: Largest BST in a Binary Tree
  5. Algorithm Interview: Level Order Traversal of Binary Tree
  6. Print a tree level-by-level, with line-breaks
  7. Algorithm Interview: Shifted String
  8. Daily Interview Problem: Find the k-th Largest Element in a List
  9. Algorithm Interview: Make the Largest Number
  10. Daily Interview Problem: Longest Substring With K Distinct Characters

Comments (1)

Read & Write - Normal - Mini - Post - All Comments - Statistics

    1.     - 2021-07-05 09:05:17 AM
 public class Main {
public static void main(String[] args) {
System.out.println("Hello World!");
int[] input = {8, 2, 3, 4, 0};
int n = input.length;
int witness = 0;
int max_so_far = Integer.MIN_VALUE;
for(int i = n-1 ; i >= 0 ; i--){
if(input[i] > max_so_far){
witness++;
max_so_far = input[i];
}
}
System.out.println(witness);
}
} 


Page Edited: May 11 2024 14:36:49 | RSS Subscription
How to Cook a Perfect Steak? | <meta name="robots" content="noindex, follow" />