File: root - text - article - 2019 - 12 - tree-serialization.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 701 Views, 19601 Search Bots | 171 Words
| Browse | Archive
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 701 Views, 19601 Search Bots | 171 Words
| Browse | Archive
Hi, here's your problem today. This problem was recently asked by Apple:
You are given the root of a binary tree. You need to implement 2 functions:
1. serialize(root) which serializes the tree into a string representation
2. deserialize(s) which deserializes the string back to the original tree that it represents
For this problem, often you will be asked to design your own serialization format. However, for simplicity, let's use the pre-order traversal of the tree. Here's your starting point:
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Cateogry: Computing | 701 Views, 19601 Search Bots | 171 Words You are given the root of a binary tree. You need to implement 2 functions:
1. serialize(root) which serializes the tree into a string representation
2. deserialize(s) which deserializes the string back to the original tree that it represents
For this problem, often you will be asked to design your own serialization format. However, for simplicity, let's use the pre-order traversal of the tree. Here's your starting point:
class Node:
def __init__(self, val, left=None, right=None):
self.val = val
self.left = left
self.right = right
def __str__(self):
# pre-order printing of the tree.
result = ''
result += str(self.val)
if self.left:
result += str(self.left)
if self.right:
result += str(self.right)
return result
def serialize(root):
# Fill this in.
def deserialize(data):
# Fill this in.
# 1
# / \
# 3 4
# / \ \
# 2 5 7
tree = Node(1)
tree.left = Node(3)
tree.left.left = Node(2)
tree.left.right = Node(5)
tree.right = Node(4)
tree.right.right = Node(7)
print serialize(tree)
# 1 3 2 # # 5 # # 4 # 7 # #
print deserialize('1 3 2 # # 5 # # 4 # 7 # #')
# 132547
Related Articles
- Fibonacci coding
- Daily Interview Puzzle: Intersection of Linked Lists
- Plus One
- [Daily Problem] Add two numbers as a linked list
- Daily Interview Problem: Deepest Node in a Binary Tree
- Algorithm Interview: Make the Largest Number
- Algorithm Interview: Lowest Common Ancestor of 2 Nodes in Binary Tree
- Daily Interview Problem: Minimum Removals for Valid Parenthesis
- Linode Support Ticket 10029540 - Other - Important Notice Regarding Ubuntu 17.10 Image
- Two Tricks of Delphi
©2006~2024 SteakOverCooked - 0.00846 Seconds(s) - 6447.599 KB/s - 44 Online Memory: 517.7 KB
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - Server PHP Version: 7.4.33
How to Cook a Perfect Steak? | <meta name="robots" content="noindex, follow" />
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - Server PHP Version: 7.4.33
Comments (0)
Read & Write - Normal - Mini - Post - All Comments - Statistics
Be the first one to comment this page !