File: root - text - article - 2019 - 12 - tree-serialization.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 444 Views, 17657 Search Bots | 171 Words
| Browse | Archive
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 444 Views, 17657 Search Bots | 171 Words
| Browse | Archive
Hi, here's your problem today. This problem was recently asked by Apple:
You are given the root of a binary tree. You need to implement 2 functions:
1. serialize(root) which serializes the tree into a string representation
2. deserialize(s) which deserializes the string back to the original tree that it represents
For this problem, often you will be asked to design your own serialization format. However, for simplicity, let's use the pre-order traversal of the tree. Here's your starting point:
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Cateogry: Computing | 444 Views, 17657 Search Bots | 171 Words You are given the root of a binary tree. You need to implement 2 functions:
1. serialize(root) which serializes the tree into a string representation
2. deserialize(s) which deserializes the string back to the original tree that it represents
For this problem, often you will be asked to design your own serialization format. However, for simplicity, let's use the pre-order traversal of the tree. Here's your starting point:
class Node:
def __init__(self, val, left=None, right=None):
self.val = val
self.left = left
self.right = right
def __str__(self):
# pre-order printing of the tree.
result = ''
result += str(self.val)
if self.left:
result += str(self.left)
if self.right:
result += str(self.right)
return result
def serialize(root):
# Fill this in.
def deserialize(data):
# Fill this in.
# 1
# / \
# 3 4
# / \ \
# 2 5 7
tree = Node(1)
tree.left = Node(3)
tree.left.left = Node(2)
tree.left.right = Node(5)
tree.right = Node(4)
tree.right.right = Node(7)
print serialize(tree)
# 1 3 2 # # 5 # # 4 # 7 # #
print deserialize('1 3 2 # # 5 # # 4 # 7 # #')
# 132547
Related Articles
- Algorithm Interview: Permutations of numbers
- Algorithm Interview: String Compression
- Daily Interview Problem: Decode String
- Patterns for breaking down questions you haven
- Algorithm Interview: Level Order Traversal of Binary Tree
- [Daily Problem] Validate Balanced Parentheses
- Invert a Binary Tree
- Two Tricks of Delphi
- Daily Interview Problem: Group Words that are Anagrams
- Algorithm Interview: Lowest Common Ancestor of 2 Nodes in Binary Tree
©2006~2024 SteakOverCooked - 0.02956 Seconds(s) - 686.699 KB/s - 27 Online Memory: 494.31 KB
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - Server PHP Version: 7.4.33
How to Cook a Perfect Steak? | <meta name="robots" content="noindex, follow" />
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - Server PHP Version: 7.4.33
Comments (0)
Read & Write - Normal - Mini - Post - All Comments - Statistics
Be the first one to comment this page !