File: root - text - article - 2019 - 12 - tree-serialization.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 433 Views, 16996 Search Bots | 171 Words
| Browse | Archive
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 433 Views, 16996 Search Bots | 171 Words
| Browse | Archive
Hi, here's your problem today. This problem was recently asked by Apple:
You are given the root of a binary tree. You need to implement 2 functions:
1. serialize(root) which serializes the tree into a string representation
2. deserialize(s) which deserializes the string back to the original tree that it represents
For this problem, often you will be asked to design your own serialization format. However, for simplicity, let's use the pre-order traversal of the tree. Here's your starting point:
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Cateogry: Computing | 433 Views, 16996 Search Bots | 171 Words You are given the root of a binary tree. You need to implement 2 functions:
1. serialize(root) which serializes the tree into a string representation
2. deserialize(s) which deserializes the string back to the original tree that it represents
For this problem, often you will be asked to design your own serialization format. However, for simplicity, let's use the pre-order traversal of the tree. Here's your starting point:
class Node:
def __init__(self, val, left=None, right=None):
self.val = val
self.left = left
self.right = right
def __str__(self):
# pre-order printing of the tree.
result = ''
result += str(self.val)
if self.left:
result += str(self.left)
if self.right:
result += str(self.right)
return result
def serialize(root):
# Fill this in.
def deserialize(data):
# Fill this in.
# 1
# / \
# 3 4
# / \ \
# 2 5 7
tree = Node(1)
tree.left = Node(3)
tree.left.left = Node(2)
tree.left.right = Node(5)
tree.right = Node(4)
tree.right.right = Node(7)
print serialize(tree)
# 1 3 2 # # 5 # # 4 # 7 # #
print deserialize('1 3 2 # # 5 # # 4 # 7 # #')
# 132547
Related Articles
- Most Frequent Subtree Sum
- Two Tricks of Delphi
- Algorithm Interview Question: Nth Fibonacci Number
- Making a Height Balanced Binary Search Tree
- Floor and Ceiling of a Binary Search Tree
- Daily Interview Problem: Group Words that are Anagrams
- Algorithm Interview Question: H-Index
- Daily Interview Problem: Reverse Words in a String
- Daily Interview Puzzle: Falling Dominoes
- Daily Interview Problem: Running Median
©2006~2024 SteakOverCooked - 0.0198 Seconds(s) - 1033.825 KB/s - 76 Online Memory: 493.78 KB
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - Server PHP Version: 7.4.33
How to Cook a Perfect Steak? | <meta name="robots" content="noindex, follow" />
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - Server PHP Version: 7.4.33
Comments (0)
Read & Write - Normal - Mini - Post - All Comments - Statistics
Be the first one to comment this page !