File: root - text - article - 2019 - 12 - tree-serialization.txt
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Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 432 Views, 16419 Search Bots | 171 Words
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Hi, here's your problem today. This problem was recently asked by Apple:
You are given the root of a binary tree. You need to implement 2 functions:
1. serialize(root) which serializes the tree into a string representation
2. deserialize(s) which deserializes the string back to the original tree that it represents
For this problem, often you will be asked to design your own serialization format. However, for simplicity, let's use the pre-order traversal of the tree. Here's your starting point:
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Cateogry: Computing | 432 Views, 16419 Search Bots | 171 Words You are given the root of a binary tree. You need to implement 2 functions:
1. serialize(root) which serializes the tree into a string representation
2. deserialize(s) which deserializes the string back to the original tree that it represents
For this problem, often you will be asked to design your own serialization format. However, for simplicity, let's use the pre-order traversal of the tree. Here's your starting point:
class Node:
def __init__(self, val, left=None, right=None):
self.val = val
self.left = left
self.right = right
def __str__(self):
# pre-order printing of the tree.
result = ''
result += str(self.val)
if self.left:
result += str(self.left)
if self.right:
result += str(self.right)
return result
def serialize(root):
# Fill this in.
def deserialize(data):
# Fill this in.
# 1
# / \
# 3 4
# / \ \
# 2 5 7
tree = Node(1)
tree.left = Node(3)
tree.left.left = Node(2)
tree.left.right = Node(5)
tree.right = Node(4)
tree.right.right = Node(7)
print serialize(tree)
# 1 3 2 # # 5 # # 4 # 7 # #
print deserialize('1 3 2 # # 5 # # 4 # 7 # #')
# 132547
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