File: root - text - article - 2020 - 02 - compare-version-numbers.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 513 Views, 23362 Search Bots | 192 Words
| Browse | Archive
![Subscribe to Feed Burner Subscribe to Feed Burner](/images/form/rss.gif)
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 513 Views, 23362 Search Bots | 192 Words
![Subscribe to Feed Burner Subscribe to Feed Burner](/images/form/rss.gif)
Hi, here's your problem today. This problem was recently asked by Amazon:
Version numbers are strings that are used to identify unique states of software products. A version number is in the format a.b.c.d. and so on where a, b, etc. are numeric strings separated by dots. These generally represent a hierarchy from major to minor changes. Given two version numbers version1 and version2, conclude which is the latest version number. Your code should do the following:
If version1 > version2 return 1.
If version1 < version2 return -1.
Otherwise return 0.
Note that the numeric strings such as a, b, c, d, etc. may have leading zeroes, and that the version strings do not start or end with dots. Unspecified level revision numbers default to 0.
Example:
Input:
version1 = "1.0.33"
version2 = "1.0.27"
Output: 1
#version1 > version2
Input:
version1 = "0.1"
version2 = "1.1"
Output: -1
#version1 < version2
Input:
version1 = "1.01"
version2 = "1.001"
Output: 0
#ignore leading zeroes, 01 and 001 represent the same number.
Input:
version1 = "1.0"
version2 = "1.0.0"
Output: 0
#version1 does not have a 3rd level revision number, which
defaults to "0"
Here's a starting point
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Cateogry: Computing | 513 Views, 23362 Search Bots | 192 Words Version numbers are strings that are used to identify unique states of software products. A version number is in the format a.b.c.d. and so on where a, b, etc. are numeric strings separated by dots. These generally represent a hierarchy from major to minor changes. Given two version numbers version1 and version2, conclude which is the latest version number. Your code should do the following:
If version1 > version2 return 1.
If version1 < version2 return -1.
Otherwise return 0.
Note that the numeric strings such as a, b, c, d, etc. may have leading zeroes, and that the version strings do not start or end with dots. Unspecified level revision numbers default to 0.
Example:
Input:
version1 = "1.0.33"
version2 = "1.0.27"
Output: 1
#version1 > version2
Input:
version1 = "0.1"
version2 = "1.1"
Output: -1
#version1 < version2
Input:
version1 = "1.01"
version2 = "1.001"
Output: 0
#ignore leading zeroes, 01 and 001 represent the same number.
Input:
version1 = "1.0"
version2 = "1.0.0"
Output: 0
#version1 does not have a 3rd level revision number, which
defaults to "0"
Here's a starting point
class Solution:
def compareVersion(self, version1, version2):
# Fill this in.
version1 = "1.0.1"
version2 = "1"
print(Solution().compareVersion(version1, version2))
# 1
![Subscribe to Feed Burner Subscribe to Feed Burner](/images/form/rss.gif)
Related Articles
- Daily Interview Problem: Product of Array Except Self
- Algorithm Interview: Determine If Linked List is Palindrome
- Autorun.inf Virus Protection
- Maximum In A Stack
- Daily Interview Problem: Reverse Integer
- Daily Interview Problem: Find the k-th Largest Element in a List
- Daily Interview Problem: Min Range Needed to Sort
- Algorithm Interview: Level Order Traversal of Binary Tree
- How to Play WAV music under DOS?
- Invert a Binary Tree
©2006~2024 SteakOverCooked - 0.01317 Seconds(s) - 4148.722 KB/s - 146 Online
Memory: 516.56 KB
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - Server PHP Version: 7.4.33
How to Cook a Perfect Steak? | <meta name="robots" content="noindex, follow" />
![](/images/top.jpg)
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - Server PHP Version: 7.4.33
Read & Write - Normal - Mini - Post - All Comments - Statistics
Be the first one to comment this page !