To the Top
File:  root - text - article - 2020 - 02 - most-frequent-subtree-sum.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 261 Views, 19165 Search Bots | 147 Words

Subscribe to Feed Burner | Browse | Archive
Hi, here's your problem today. This problem was recently asked by LinkedIn:

Given a binary tree, find the most frequent subtree sum.

Example:


3
/ \
1 -3

The above tree has 3 subtrees. The root node with 3, and the 2 leaf nodes, which gives us a total of 3 subtree sums. The root node has a sum of 1 (3 + 1 + -3), the left leaf node has a sum of 1, and the right leaf node has a sum of -3. Therefore the most frequent subtree sum is 1.

If there is a tie between the most frequent sum, you can return any one of them.

Here's some starter code for the problem:


class Node():
def __init__(self, value, left=None, right=None):
self.val = value
self.left = left
self.right = right

def most_freq_subtree_sum(root):
# fill this in.

root = Node(3, Node(1), Node(-3))
print(most_freq_subtree_sum(root))
# 1
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Cateogry: Computing | 261 Views, 19165 Search Bots | 147 Words Subscribe to Feed Burner

Related Articles

  1. [Daily Problem] Validate Balanced Parentheses
  2. Daily Interview Problem: Count Number of Unival Subtrees
  3. Algorithm Interview: Subarray With Target Sum
  4. Sorting a list with 3 unique numbers
  5. Daily Interview Problem: Word Ordering in a Different Alphabetical Order
  6. Daily Interview Problem: Room scheduling
  7. Spreadsheet Column Title
  8. New Vulnerabilities (CVE-2016-4581) have been detected in CentOS/RHEL/CloudLinux 7
  9. Fibonacci coding
  10. Consecutive Ones

Comments (0)

    Be the first one to comment this page !


Page Edited: May 11 2024 14:36:49 | RSS Subscription
How to Cook a Perfect Steak? | <meta name="robots" content="noindex, follow" />