File: root - text - article - 2020 - 02 - staying-on-a-chess-board.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 411 Views, 24533 Search Bots | 94 Words
| Browse | Archive
![Subscribe to Feed Burner Subscribe to Feed Burner](/images/form/rss.gif)
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 411 Views, 24533 Search Bots | 94 Words
![Subscribe to Feed Burner Subscribe to Feed Burner](/images/form/rss.gif)
Hi, here's your problem today. This problem was recently asked by Google:
A chess board is an 8x8 grid. Given a knight at any position (x, y) and a number of moves k, we want to figure out after k random moves by a knight, the probability that the knight will still be on the chessboard. Once the knight leaves the board it cannot move again and will be considered off the board.
Here's some starter code:
def is_knight_on_board(x, y, k, cache={}):
# Fill this in.
print is_knight_on_board(0, 0, 1)
# 0.25
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Cateogry: Computing | 411 Views, 24533 Search Bots | 94 Words A chess board is an 8x8 grid. Given a knight at any position (x, y) and a number of moves k, we want to figure out after k random moves by a knight, the probability that the knight will still be on the chessboard. Once the knight leaves the board it cannot move again and will be considered off the board.
Here's some starter code:
def is_knight_on_board(x, y, k, cache={}):
# Fill this in.
print is_knight_on_board(0, 0, 1)
# 0.25
![Subscribe to Feed Burner Subscribe to Feed Burner](/images/form/rss.gif)
Related Articles
- Absolute Path
- A trick for getting good at coding interviews FASTER
- Daily Interview Problem:Create a balanced binary search tree
- Algorithm Interview Question: Nth Fibonacci Number
- Daily Interview Problem: Tree Serialization
- Daily Interview Problem: Minimum Removals for Valid Parenthesis
- New Vulnerabilities (CVE-2016-4581) have been detected in CentOS/RHEL/CloudLinux 7
- Fix Brackets
- Windows Scripting
- Autorun.inf Virus Protection
©2006~2024 SteakOverCooked - 0.01465 Seconds(s) - 2616.1 KB/s - 30 Online
Memory: 534.16 KB
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - Server PHP Version: 7.4.33
How to Cook a Perfect Steak? | <meta name="robots" content="index, follow">
![](/images/top.jpg)
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - Server PHP Version: 7.4.33
Read & Write - Normal - Mini - Post - All Comments - Statistics
Be the first one to comment this page !