To the Top
File:  root - text - article - 2020 - 02 - staying-on-a-chess-board.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 417 Views, 25328 Search Bots | 94 Words

Subscribe to Feed Burner | Browse | Archive
Hi, here's your problem today. This problem was recently asked by Google:

A chess board is an 8x8 grid. Given a knight at any position (x, y) and a number of moves k, we want to figure out after k random moves by a knight, the probability that the knight will still be on the chessboard. Once the knight leaves the board it cannot move again and will be considered off the board.

Here's some starter code:

def is_knight_on_board(x, y, k, cache={}):
# Fill this in.

print is_knight_on_board(0, 0, 1)
# 0.25
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Cateogry: Computing | 417 Views, 25328 Search Bots | 94 Words Subscribe to Feed Burner

Related Articles

  1. Daily Interview Question: Word Search
  2. Algorithm Interview: No Adjacent Repeating Characters
  3. Generate All IP Addresses
  4. Daily Interview Problem: Buddy Strings
  5. Linode Support Ticket 10029540 - Other - Important Notice Regarding Ubuntu 17.10 Image
  6. Daily Interview Question: Create a Simple Calculator
  7. Daily Interview Problem: Arithmetic Binary Tree
  8. A trick for getting good at coding interviews FASTER
  9. Daily Interview Problem: Find the Number of Islands
  10. Daily Interview Problem: Deepest Node in a Binary Tree

Comments (0)

    Be the first one to comment this page !


Page Edited: May 11 2024 14:36:49 | RSS Subscription
How to Cook a Perfect Steak? | <meta name="robots" content="index, follow">