File: root - text - article - 2020 - 02 - top-k-frequent-words.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 320 Views, 20300 Search Bots | 102 Words
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Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 320 Views, 20300 Search Bots | 102 Words
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Hi, here's your problem today. This problem was recently asked by AirBNB:
Given a non-empty list of words, return the k most frequent words. The output should be sorted from highest to lowest frequency, and if two words have the same frequency, the word with lower alphabetical order comes first. Input will contain only lower-case letters.
Example:
Input: ["daily", "interview", "pro", "pro", "for", "daily", "pro", "problems"], k = 2
Output: ["pro", "daily"]
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Cateogry: Computing | 320 Views, 20300 Search Bots | 102 Words Given a non-empty list of words, return the k most frequent words. The output should be sorted from highest to lowest frequency, and if two words have the same frequency, the word with lower alphabetical order comes first. Input will contain only lower-case letters.
Example:
Input: ["daily", "interview", "pro", "pro", "for", "daily", "pro", "problems"], k = 2
Output: ["pro", "daily"]
class Solution(object):
def topKFrequent(self, words, k):
# Fill this in.
words = ["daily", "interview", "pro", "pro", "for", "daily", "pro", "problems"]
k = 2
print(Solution().topKFrequent(words, k))
# ['pro', 'daily']
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