To the Top
File:  root - text - article - 2020 - 02 - top-k-frequent-words.txt
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Category: Computing | 314 Views, 19226 Search Bots | 102 Words

Subscribe to Feed Burner | Browse | Archive
Hi, here's your problem today. This problem was recently asked by AirBNB:

Given a non-empty list of words, return the k most frequent words. The output should be sorted from highest to lowest frequency, and if two words have the same frequency, the word with lower alphabetical order comes first. Input will contain only lower-case letters.

Example:
Input: ["daily", "interview", "pro", "pro", "for", "daily", "pro", "problems"], k = 2
Output: ["pro", "daily"]


class Solution(object):
def topKFrequent(self, words, k):
# Fill this in.

words = ["daily", "interview", "pro", "pro", "for", "daily", "pro", "problems"]
k = 2
print(Solution().topKFrequent(words, k))
# ['pro', 'daily']
Tags: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | English | Home Page | Cateogry: Computing | 314 Views, 19226 Search Bots | 102 Words Subscribe to Feed Burner

Related Articles

  1. Algorithm Interview: Convert Roman Numerals to Decimal
  2. Compare Version Numbers
  3. Daily Interview Problem: Maximum Profit From Stocks
  4. ImageMagick Vulnerabilities -  CVE-2016–3714
  5. Daily Interview Problem: Sort Colors
  6. Daily Interview Problem: Running Median
  7. Algorithm Interview: Longest Consecutive Sequence
  8. Binary Tree Level with Minimum Sum
  9. [Daily Problem] Remove k-th Last Element From Linked List
  10. [Daily Problem] Move Zeros

Comments (0)

Your Email (Domain Part Not Exposed):

Your Comments:

Privately By Mail Colors More Smileys S x y @

Verification (Click Image 2 Refresh):

    Be the first one to comment this page !


Page Edited: May 11 2024 14:36:49 | RSS Subscription
How to Cook a Perfect Steak? | <meta name="robots" content="noindex, follow" />