文件: root - text - article - 2019 - 10 - non-decreasing-array-with-single-modification.txt
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标签: 每日算法题, 算法, 数据结构, 面试题, Daily Problem, Data Structures and Algorithms, | 英文 | 主页 | 类别: 计算机科学 | 473 次阅读, 28396 次搜索 | 126 个单词
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Hi, here's your problem today. This problem was recently asked by Microsoft:
You are given an array of integers in an arbitrary order. Return whether or not it is possible to make the array non-decreasing by modifying at most 1 element to any value.
We define an array is non-decreasing if array[i] <= array[i + 1] holds for every i (1 <= i < n).
Example:
[13, 4, 7] should return true, since we can modify 13 to any value 4 or less, to make it non-decreasing.
[13, 4, 1] however, should return false, since there is no way to modify just one element to make the array non-decreasing.
Here is the function signature:
Can you find a solution in O(n) time?
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Problem, Data Structures and Algorithms, | 英文 | 主页 | 类别: 计算机科学 | 473 次阅读, 28396 次搜索 | 126 个单词 You are given an array of integers in an arbitrary order. Return whether or not it is possible to make the array non-decreasing by modifying at most 1 element to any value.
We define an array is non-decreasing if array[i] <= array[i + 1] holds for every i (1 <= i < n).
Example:
[13, 4, 7] should return true, since we can modify 13 to any value 4 or less, to make it non-decreasing.
[13, 4, 1] however, should return false, since there is no way to modify just one element to make the array non-decreasing.
Here is the function signature:
def check(lst):
# Fill this in.
print check([13, 4, 7])
# True
print check([5,1,3,2,5])
# False
Can you find a solution in O(n) time?
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