文件: root - text - article - 2019 - 11 - Remove-k-th-Last-Element-From-Linked-List.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 382 次阅读, 29169 次搜索 | 120 个单词
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标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 382 次阅读, 29169 次搜索 | 120 个单词
| 浏览 | 博客存档
Hi, here's your problem today. This problem was recently asked by AirBNB:
You are given a singly linked list and an integer k. Return the linked list, removing the k-th last element from the list.
Try to do it in a single pass and using constant space.
Here's a starting point:
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 382 次阅读, 29169 次搜索 | 120 个单词 You are given a singly linked list and an integer k. Return the linked list, removing the k-th last element from the list.
Try to do it in a single pass and using constant space.
Here's a starting point:
class Node:
def __init__(self, val, next=None):
self.val = val
self.next = next
def __str__(self):
current_node = self
result = []
while current_node:
result.append(current_node.val)
current_node = current_node.next
return str(result)
def remove_kth_from_linked_list(head, k):
# Fill this in
head = Node(1, Node(2, Node(3, Node(4, Node(5)))))
print(head)
# [1, 2, 3, 4, 5]
head = remove_kth_from_linked_list(head, 3)
print(head)
# [1, 2, 4, 5]
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