文件: root - text - article - 2019 - 11 - create-a-balanced-binary-search-tree.txt
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标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 472 次阅读, 22549 次搜索 | 111 个单词
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Hi, here's your problem today. This problem was recently asked by LinkedIn:
Given a sorted list of numbers, change it into a balanced binary search tree. You can assume there will be no duplicate numbers in the list.
Here's a starting point:
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 472 次阅读, 22549 次搜索 | 111 个单词 Given a sorted list of numbers, change it into a balanced binary search tree. You can assume there will be no duplicate numbers in the list.
Here's a starting point:
from collections import deque
class Node:
def __init__(self, value, left=None, right=None):
self.value = value
self.left = left
self.right = right
def __str__(self):
# level-by-level pretty-printer
nodes = deque([self])
answer = ''
while len(nodes):
node = nodes.popleft()
if not node:
continue
answer += str(node.value)
nodes.append(node.left)
nodes.append(node.right)
return answer
def createBalancedBST(nums):
# Fill this in.
print createBalancedBST([1, 2, 3, 4, 5, 6, 7])
# 4261357
# 4
# / \
# 2 6
#/ \ / \
#1 3 5 7
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