文件: root - text - article - 2019 - 11 - falling-dominoes.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, | 英文 | 主页 | 类别: 计算机科学 | 493 次阅读, 16193 次搜索 | 117 个单词
| 浏览 | 博客存档
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, | 英文 | 主页 | 类别: 计算机科学 | 493 次阅读, 16193 次搜索 | 117 个单词
| 浏览 | 博客存档
Hi, here's your problem today. This problem was recently asked by Twitter:
Given a string with the initial condition of dominoes, where:
. represents that the domino is standing still
L represents that the domino is falling to the left side
R represents that the domino is falling to the right side
Figure out the final position of the dominoes. If there are dominoes that get pushed on both ends, the force cancels out and that domino remains upright.
Example:
Input: ..R...L..R.
Output: ..RR.LL..RR
Here is your starting point:
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, | 英文 | 主页 | 类别: 计算机科学 | 493 次阅读, 16193 次搜索 | 117 个单词 Given a string with the initial condition of dominoes, where:
. represents that the domino is standing still
L represents that the domino is falling to the left side
R represents that the domino is falling to the right side
Figure out the final position of the dominoes. If there are dominoes that get pushed on both ends, the force cancels out and that domino remains upright.
Example:
Input: ..R...L..R.
Output: ..RR.LL..RR
Here is your starting point:
class Solution(object):
def pushDominoes(self, dominoes):
# Fill this in.
print Solution().pushDominoes('..R...L..R.')
# ..RR.LL..RR
猜您喜欢...
- Algorithm Interview: Determine If Linked List is Palindrome
- Algorithm Interview: Convert Roman Numerals to Decimal
- Algorithm Interview: Lowest Common Ancestor of 2 Nodes in Binary Tree
- Making a Height Balanced Binary Search Tree
- Compare Version Numbers
- Plus One
- Skip the readings, focus on problems. And use all the hints!
- Reverse a Linked List
- ImageMagick Vulnerabilities - CVE-2016–3714
- Sorting a list with 3 unique numbers
©2006~2024 牛排过熟 - 0.0138 秒 - 3927.838 KB/s - 26 在线 内存: 519.18 KB
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - 服务器 PHP 版本号: 7.4.33
牛排怎么做才好吃? | <meta name="机器人" content="不索引, 跟踪" />
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - 服务器 PHP 版本号: 7.4.33
评论 (0)
读写完全 - 一般 - 最小 - 表格 - 所有评论 - 统计
当前页暂时没有评论。