文件: root - text - article - 2019 - 11 - merge-k-sorted-linked-list.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 399 次阅读, 20853 次搜索 | 98 个单词
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标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 399 次阅读, 20853 次搜索 | 98 个单词
| 浏览 | 博客存档
Hi, here's your problem today. This problem was recently asked by Twitter:
You are given an array of k sorted singly linked lists. Merge the linked lists into a single sorted linked list and return it.
Here's your starting point:
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 399 次阅读, 20853 次搜索 | 98 个单词 You are given an array of k sorted singly linked lists. Merge the linked lists into a single sorted linked list and return it.
Here's your starting point:
class Node(object):
def __init__(self, val, next=None):
self.val = val
self.next = next
def __str__(self):
c = self
answer = ""
while c:
answer += str(c.val) if c.val else ""
c = c.next
return answer
def merge(lists):
# Fill this in.
a = Node(1, Node(3, Node(5)))
b = Node(2, Node(4, Node(6)))
print merge([a, b])
# 123456
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