文件: root - text - article - 2019 - 12 - jump-to-the-end.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 637 次阅读, 18001 次搜索 | 86 个单词
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标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 637 次阅读, 18001 次搜索 | 86 个单词
| 浏览 | 博客存档
Hi, here's your problem today. This problem was recently asked by Facebook:
Starting at index 0, for an element n at index i, you are allowed to jump at most n indexes ahead. Given a list of numbers, find the minimum number of jumps to reach the end of the list.
Example:
Input: [3, 2, 5, 1, 1, 9, 3, 4]
Output: 2
Explanation:
The minimum number of jumps to get to the end of the list is 2:
3 - 5 - 4
Here's a starting point:
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 637 次阅读, 18001 次搜索 | 86 个单词 Starting at index 0, for an element n at index i, you are allowed to jump at most n indexes ahead. Given a list of numbers, find the minimum number of jumps to reach the end of the list.
Example:
Input: [3, 2, 5, 1, 1, 9, 3, 4]
Output: 2
Explanation:
The minimum number of jumps to get to the end of the list is 2:
3 - 5 - 4
Here's a starting point:
def jumpToEnd(nums):
# Fill this in.
print jumpToEnd([3, 2, 5, 1, 1, 9, 3, 4])
# 2
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