页面顶部 Top
文件:  root - text - article - 2019 - 12 - jump-to-the-end.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 560 次阅读, 14612 次搜索 | 86 个单词

定阅此目录的博客 | 浏览 | 博客存档
Hi, here's your problem today. This problem was recently asked by Facebook:

Starting at index 0, for an element n at index i, you are allowed to jump at most n indexes ahead. Given a list of numbers, find the minimum number of jumps to reach the end of the list.

Example:
Input: [3, 2, 5, 1, 1, 9, 3, 4]
Output: 2
Explanation:

The minimum number of jumps to get to the end of the list is 2:
3 - 5 - 4

Here's a starting point:


def jumpToEnd(nums):
# Fill this in.

print jumpToEnd([3, 2, 5, 1, 1, 9, 3, 4])
# 2
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 560 次阅读, 14612 次搜索 | 86 个单词 定阅此目录的博客

猜您喜欢...

  1. Number of Ways to Climb Stairs
  2. New Vulnerabilities (CVE-2016-4581) have been detected in CentOS/RHEL/CloudLinux 7
  3. Algorithm Interview: Permutations of numbers
  4. Progess made
  5. Palindrome Integers
  6. Detect Linked List Cycle
  7. ImageMagick Vulnerabilities -  CVE-2016–3714
  8. Algorithm Interview: Shifted String
  9. Daily Interview Problem: Merge List Of Number Into Ranges
  10. Two Tricks of Delphi

评论 (0)

    当前页暂时没有评论。


最后更新: October 30 2020 14:21:12 | RSS Subscription
牛排怎么做才好吃? | <meta name="机器人" content="不索引, 跟踪" />