文件: root - text - article - 2019 - 12 - minimum-removals-for-valid-parenthesis.txt.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 446 次阅读, 20027 次搜索 | 74 个单词
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标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 446 次阅读, 20027 次搜索 | 74 个单词
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Hi, here's your problem today. This problem was recently asked by Uber:
You are given a string of parenthesis. Return the minimum number of parenthesis that would need to be removed in order to make the string valid. "Valid" means that each open parenthesis has a matching closed parenthesis.
Example:
"()())()"
The following input should return 1.
")("
Here's a start:
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 446 次阅读, 20027 次搜索 | 74 个单词 You are given a string of parenthesis. Return the minimum number of parenthesis that would need to be removed in order to make the string valid. "Valid" means that each open parenthesis has a matching closed parenthesis.
Example:
"()())()"
The following input should return 1.
")("
Here's a start:
def count_invalid_parenthesis(string):
# Fill this in.
print count_invalid_parenthesis("()())()")
# 1
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