文件: root - text - article - 2019 - 12 - tree-serialization.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 432 次阅读, 16424 次搜索 | 171 个单词
| 浏览 | 博客存档
![定阅此目录的博客 定阅此目录的博客](/images/form/rss.gif)
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 432 次阅读, 16424 次搜索 | 171 个单词
![定阅此目录的博客 定阅此目录的博客](/images/form/rss.gif)
Hi, here's your problem today. This problem was recently asked by Apple:
You are given the root of a binary tree. You need to implement 2 functions:
1. serialize(root) which serializes the tree into a string representation
2. deserialize(s) which deserializes the string back to the original tree that it represents
For this problem, often you will be asked to design your own serialization format. However, for simplicity, let's use the pre-order traversal of the tree. Here's your starting point:
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 432 次阅读, 16424 次搜索 | 171 个单词 You are given the root of a binary tree. You need to implement 2 functions:
1. serialize(root) which serializes the tree into a string representation
2. deserialize(s) which deserializes the string back to the original tree that it represents
For this problem, often you will be asked to design your own serialization format. However, for simplicity, let's use the pre-order traversal of the tree. Here's your starting point:
class Node:
def __init__(self, val, left=None, right=None):
self.val = val
self.left = left
self.right = right
def __str__(self):
# pre-order printing of the tree.
result = ''
result += str(self.val)
if self.left:
result += str(self.left)
if self.right:
result += str(self.right)
return result
def serialize(root):
# Fill this in.
def deserialize(data):
# Fill this in.
# 1
# / \
# 3 4
# / \ \
# 2 5 7
tree = Node(1)
tree.left = Node(3)
tree.left.left = Node(2)
tree.left.right = Node(5)
tree.right = Node(4)
tree.right.right = Node(7)
print serialize(tree)
# 1 3 2 # # 5 # # 4 # 7 # #
print deserialize('1 3 2 # # 5 # # 4 # 7 # #')
# 132547
![定阅此目录的博客 定阅此目录的博客](/images/form/rss.gif)
猜您喜欢...
- Daily Interview Problem: Count Number of Unival Subtrees
- Daily Interview Problem: Queue Using Two Stacks
- Daily Interview Puzzle: Intersection of Linked Lists
- Algorithm Interview Question: H-Index
- Algorithm Interview: Determine If Linked List is Palindrome
- Daily Interview Problem: Get all Values at a Certain Height in a Binary Tree
- Algorithm Interview: Make the Largest Number
- Daily Interview Puzzle: Minimum Size Subarray Sum
- Sorting a list with 3 unique numbers
- Find Pythagorean Triplets
©2006~2024 牛排过熟 - 0.01449 秒 - 1308.466 KB/s - 150 在线
内存: 494.77 KB
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - 服务器 PHP 版本号: 7.4.33
牛排怎么做才好吃? | <meta name="机器人" content="不索引, 跟踪" />
![](/images/top.jpg)
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - 服务器 PHP 版本号: 7.4.33
读写完全 - 一般 - 最小 - 表格 - 所有评论 - 统计
当前页暂时没有评论。