页面顶部 Top
文件:  root - text - article - 2020 - 01 - determine-if-linked-list-is-palindrome.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 182 次阅读, 22492 次搜索 | 102 个单词

定阅此目录的博客 | 浏览 | 博客存档
Hi, here's your problem today. This problem was recently asked by Microsoft:

You are given a doubly linked list. Determine if it is a palindrome.

Can you do this for a singly linked list?


class Node(object):
def __init__(self, val):
self.val = val
self.next = None
self.prev = None

def is_palindrome(node):
# Fill this in.

node = Node('a')
node.next = Node('b')
node.next.prev = node
node.next.next = Node('b')
node.next.next.prev = node.next
node.next.next.next = Node('a')
node.next.next.next.prev = node.next.next

print is_palindrome(node)
# True
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 182 次阅读, 22492 次搜索 | 102 个单词 定阅此目录的博客

猜您喜欢...

  1. CVE-2015-8874 - cPanel EasyApache Vulnerabilities
  2. Windows Scripting
  3. Making a Height Balanced Binary Search Tree
  4. Daily Interview Problem: Buddy Strings
  5. Invert a Binary Tree
  6. Non-decreasing Array with Single Modification
  7. Algorithm Interview: Longest Consecutive Sequence
  8. Two-Sum
  9. Consecutive Ones
  10. Algorithm Interview: Shifted String

评论 (0)

    当前页暂时没有评论。


最后更新: October 30 2020 14:21:12 | RSS Subscription
牛排怎么做才好吃? | <meta name="机器人" content="不索引, 跟踪" />