文件: root - text - article - 2020 - 01 - find-the-single-element-in-an-array-of-duplicates.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 204 次阅读, 31141 次搜索 | 68 个单词
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标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 204 次阅读, 31141 次搜索 | 68 个单词
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Hi, here's your problem today. This problem was recently asked by Apple:
Given an array of integers, arr, where all numbers occur twice except one number which occurs once, find the number. Your solution should ideally be O(n) time and use constant extra space.
Example:
Input: arr = [7, 3, 5, 5, 4, 3, 4, 8, 8]
Output: 7
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 204 次阅读, 31141 次搜索 | 68 个单词 Given an array of integers, arr, where all numbers occur twice except one number which occurs once, find the number. Your solution should ideally be O(n) time and use constant extra space.
Example:
Input: arr = [7, 3, 5, 5, 4, 3, 4, 8, 8]
Output: 7
class Solution(object):
def findSingle(self, nums):
# Fill this in.
nums = [1, 1, 3, 4, 4, 5, 6, 5, 6]
print(Solution().findSingle(nums))
# 3
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