文件: root - text - article - 2020 - 02 - kaprekar.txt.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 1154 次阅读, 23700 次搜索 | 134 个单词
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标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 1154 次阅读, 23700 次搜索 | 134 个单词
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Hi, here's your problem today. This problem was recently asked by Facebook:
Kaprekar's Constant is the number 6174. This number is special because it has the property where for any 4-digit number that has 2 or more unique digits, if you repeatedly apply a certain function it always reaches the number 6174.
This certain function is as follows:
- Order the number in ascending form and descending form to create 2 numbers.
- Pad the descending number with zeros until it is 4 digits in length.
- Subtract the ascending number from the descending number.
- Repeat.
Given a number n, find the number of times the function needs to be applied to reach Kaprekar's constant. Here's some starter code:
KAPREKAR_CONSTANT = 6174
def num_kaprekar_iterations(n):
# Fill this in.
print num_kaprekar_iterations(123)
# 3
# Explanation:
# 3210 - 123 = 3087
# 8730 - 0378 = 8352
# 8532 - 2358 = 6174 (3 iterations)
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 1154 次阅读, 23700 次搜索 | 134 个单词 Kaprekar's Constant is the number 6174. This number is special because it has the property where for any 4-digit number that has 2 or more unique digits, if you repeatedly apply a certain function it always reaches the number 6174.
This certain function is as follows:
- Order the number in ascending form and descending form to create 2 numbers.
- Pad the descending number with zeros until it is 4 digits in length.
- Subtract the ascending number from the descending number.
- Repeat.
Given a number n, find the number of times the function needs to be applied to reach Kaprekar's constant. Here's some starter code:
KAPREKAR_CONSTANT = 6174
def num_kaprekar_iterations(n):
# Fill this in.
print num_kaprekar_iterations(123)
# 3
# Explanation:
# 3210 - 123 = 3087
# 8730 - 0378 = 8352
# 8532 - 2358 = 6174 (3 iterations)
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