文件: root - text - article - 2020 - 02 - print-a-tree-level-by-level,-with-line-breaks.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 663 次阅读, 28462 次搜索 | 111 个单词
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标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 663 次阅读, 28462 次搜索 | 111 个单词
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Hi, here's your problem today. This problem was recently asked by Apple:
You are given a tree, and your job is to print it level-by-level with linebreaks.
a
/ \
b c
/ \ / \
d e f g
The output should be
a
bc
defg
Here's a starting point:
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 663 次阅读, 28462 次搜索 | 111 个单词 You are given a tree, and your job is to print it level-by-level with linebreaks.
a
/ \
b c
/ \ / \
d e f g
The output should be
a
bc
defg
Here's a starting point:
from collections import deque
class Node(object):
def __init__(self, val):
self.val = val
self.left = None
self.right = None
def __str__(self):
# Fill this in.
tree = Node('a')
tree.left = Node('b')
tree.right = Node('c')
tree.left.left = Node('d')
tree.left.right = Node('e')
tree.right.left = Node('f')
tree.right.right = Node('g')
print tree
# a
# bc
# defg
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