文件: root - text - article - 2020 - 02 - staying-on-a-chess-board.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 363 次阅读, 23197 次搜索 | 94 个单词
| 浏览 | 博客存档
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 363 次阅读, 23197 次搜索 | 94 个单词
| 浏览 | 博客存档
Hi, here's your problem today. This problem was recently asked by Google:
A chess board is an 8x8 grid. Given a knight at any position (x, y) and a number of moves k, we want to figure out after k random moves by a knight, the probability that the knight will still be on the chessboard. Once the knight leaves the board it cannot move again and will be considered off the board.
Here's some starter code:
def is_knight_on_board(x, y, k, cache={}):
# Fill this in.
print is_knight_on_board(0, 0, 1)
# 0.25
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 363 次阅读, 23197 次搜索 | 94 个单词 A chess board is an 8x8 grid. Given a knight at any position (x, y) and a number of moves k, we want to figure out after k random moves by a knight, the probability that the knight will still be on the chessboard. Once the knight leaves the board it cannot move again and will be considered off the board.
Here's some starter code:
def is_knight_on_board(x, y, k, cache={}):
# Fill this in.
print is_knight_on_board(0, 0, 1)
# 0.25
猜您喜欢...
- Multitasking
- Daily Interview Problem: Contiguous Subarray with Maximum Sum
- Daily Interview Puzzle: Falling Dominoes
- CPU Utilization
- Daily Interview Problem: Maximum Profit From Stocks
- Making a Height Balanced Binary Search Tree
- Floor and Ceiling of a Binary Search Tree
- [Daily Problem] Longest Increasing Subsequence
- Detect Linked List Cycle
- Compare Version Numbers
©2006~2024 牛排过熟 - 0.02859 秒 - 1854.201 KB/s - 50 在线 内存: 528.05 KB
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - 服务器 PHP 版本号: 7.4.33
牛排怎么做才好吃? | <meta name="机器人" content="不索引, 跟踪" />
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - 服务器 PHP 版本号: 7.4.33
评论 (0)
读写完全 - 一般 - 最小 - 表格 - 所有评论 - 统计
当前页暂时没有评论。