文件: root - text - article - 2020 - 02 - staying-on-a-chess-board.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 409 次阅读, 24362 次搜索 | 94 个单词
| 浏览 | 博客存档
![定阅此目录的博客 定阅此目录的博客](/images/form/rss.gif)
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 409 次阅读, 24362 次搜索 | 94 个单词
![定阅此目录的博客 定阅此目录的博客](/images/form/rss.gif)
Hi, here's your problem today. This problem was recently asked by Google:
A chess board is an 8x8 grid. Given a knight at any position (x, y) and a number of moves k, we want to figure out after k random moves by a knight, the probability that the knight will still be on the chessboard. Once the knight leaves the board it cannot move again and will be considered off the board.
Here's some starter code:
def is_knight_on_board(x, y, k, cache={}):
# Fill this in.
print is_knight_on_board(0, 0, 1)
# 0.25
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 409 次阅读, 24362 次搜索 | 94 个单词 A chess board is an 8x8 grid. Given a knight at any position (x, y) and a number of moves k, we want to figure out after k random moves by a knight, the probability that the knight will still be on the chessboard. Once the knight leaves the board it cannot move again and will be considered off the board.
Here's some starter code:
def is_knight_on_board(x, y, k, cache={}):
# Fill this in.
print is_knight_on_board(0, 0, 1)
# 0.25
![定阅此目录的博客 定阅此目录的博客](/images/form/rss.gif)
猜您喜欢...
- Daily Interview Problem: Reverse Words in a String
- Autorun.inf Virus Protection
- Daily Interview Problem: Decode String
- Daily Interview Problem: Word Ordering in a Different Alphabetical Order
- PHP Unit Tests on VPS Server
- Skip the readings, focus on problems. And use all the hints!
- Daily Interview Problem: Look and Say Sequence
- Windows Scripting
- Algorithm Interview Question: Max and Min with Limited Comparisons
- Algorithm Interview: Convert Roman Numerals to Decimal
©2006~2024 牛排过熟 - 0.01713 秒 - 3158.307 KB/s - 55 在线
内存: 516.08 KB
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - 服务器 PHP 版本号: 7.4.33
牛排怎么做才好吃? | <meta name="机器人" content="不索引, 跟踪" />
![](/images/top.jpg)
18:54:01 up 13 days, 18:33, 2 users, load average: 0.98, 0.86, 0.73 - 服务器 PHP 版本号: 7.4.33
读写完全 - 一般 - 最小 - 表格 - 所有评论 - 统计
当前页暂时没有评论。