文件: root - text - article - 2020 - 02 - top-k-frequent-words.txt
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 319 次阅读, 19968 次搜索 | 102 个单词
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标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 319 次阅读, 19968 次搜索 | 102 个单词
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Hi, here's your problem today. This problem was recently asked by AirBNB:
Given a non-empty list of words, return the k most frequent words. The output should be sorted from highest to lowest frequency, and if two words have the same frequency, the word with lower alphabetical order comes first. Input will contain only lower-case letters.
Example:
Input: ["daily", "interview", "pro", "pro", "for", "daily", "pro", "problems"], k = 2
Output: ["pro", "daily"]
标签: 每日算法题, 算法, 数据结构, 面试题, Daily Interview Problem, Data Structures and Algorithms, Computer Programming, Python, | 英文 | 主页 | 类别: 计算机科学 | 319 次阅读, 19968 次搜索 | 102 个单词 Given a non-empty list of words, return the k most frequent words. The output should be sorted from highest to lowest frequency, and if two words have the same frequency, the word with lower alphabetical order comes first. Input will contain only lower-case letters.
Example:
Input: ["daily", "interview", "pro", "pro", "for", "daily", "pro", "problems"], k = 2
Output: ["pro", "daily"]
class Solution(object):
def topKFrequent(self, words, k):
# Fill this in.
words = ["daily", "interview", "pro", "pro", "for", "daily", "pro", "problems"]
k = 2
print(Solution().topKFrequent(words, k))
# ['pro', 'daily']
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